The density of 400cm3 of palm oil was 0.9gcm
The density of 400cm3 of palm oil was 0.9gcm-3 before frying. If the density of the oil was 0.6gm-3 after frying,assuming no loss of oil due to spilling, its new volume was
360cm3
600cm3
240cm3
800cm3
450cm3
Correct answer is B
Since no loss of oil,
Density x volume = constant
D1V1 = D2 x V2
0.9 x 400 = V2
V2 = 600cm3
Which is NOT one of the laws of solid friction? ...
From the diagram above, determine the value of the resistance X ...
The correct position for a fuse in the diagram above is ...
Which of the following devices is used to determine the relative density of an acid? ...
If the refractive index of glass is 1.5, what is the critical angle at the air-glass interface?...
A device that converts mechanical energy into electrical energy is ...