\(\begin{pmatrix} 10 & 7 \\ 12 & 9 \end{pmatrix}\)
\(\begin{pmatrix} 2 & 7 \\ 4 & 17 \end{pmatrix}\)
\(\begin{pmatrix} 10 & 4 \\ 4 & 6 \end{pmatrix}\)
\(\begin{pmatrix} 4 & 3 \\ 10 & 9 \end{pmatrix}\)
Correct answer is A
\(\begin{pmatrix} 1 & 2 \\ 0 & 3 \end{pmatrix}\); y = \(\begin{pmatrix} 2 & 1 \\ 4 & 3 \end{pmatrix}\).
= \(\begin{pmatrix} 2 + 8 & 1 + 6 \\ 0 + 12 & 0 + 9 \end{pmatrix}\)
= \(\begin{pmatrix} 10 & 7 \\ 12 & 9 \end{pmatrix}\)
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