p+qa(p−q)
p−qa(p+q)
p−qapq
pqa(p−q)
Correct answer is B
1+ax1−ax = pq by cross multiplication,
q(1 + ax) = p(1 - ax)
q + qax = p - pax
qax + pax = p - q
∴ x = p−qa(p+q)
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