Using the data in the circuit illustrated above, calculat...
Using the data in the circuit illustrated above, calculate the value of R
0.02\(\Omega\)
0.05\(\Omega\)
5.00\(\Omega\)
20.00\(\Omega\)
50.00\(\Omega\)
Correct answer is E
R = \(\frac{V}{T} = \frac{2v}{40 \times 10^{-3}}\)
= 50.00\(\Omega\)