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An object is projected with a velocity of 100m-1

An object is projected with a velocity of 100m-1 at an angle of 60° to the vertical. Calculate the time taken by the object to reach the highest point (Take g as 10ms-2

A.

5.0s

B.

8.7s

C.

10.0s

D.

17.3s

E.

20.0s

View answer & explanation

Correct answer is B

t = \(\frac{T}{2} = \frac{1}{2} = \frac{2u \sin \theta}{g} = \frac{100 \times \sin 60}{10}\)

10 sin60 = 10 x 0.8660

= 8.7

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