0, 8
-1, 53
2, 3
1, -1
Correct answer is B
2k−1k+1=3k+12k−1
(k+1)(3k+1)=(2k−1)(2k−1)
3k2+4k+1=4k2−4k+1
4k2−3k2−4k−4k+1−1=0
k2−8k=0
k(k−8)=0
∴
The terms of the sequence given k = 0: (1, -1, 1)
\implies \text{The common ratio r = -1}
The terms of the sequence given k = 8: (9, 15, 25)
\implies \text{The common ratio r = } \frac{5}{3}
The possible values of the common ratio are -1 and \frac{5}{3}.
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