If U = (1, 2, 3, 6, 7, 8, 9, 10) is the universal set. E = (10, 4, 6, 8, 10) and F = {x: 1x $^{2}$ = 2\(^{6}, x is odd}. Find (E ∩ F)', where ' means the complement of a set.

(0)

(8)

$\phi$

Correct answer is D

U = (1, 2, 3, 6, 7, 8, 9, 10)

E = (10, 4, 6, 8, 10)

F = (x : x $^2$ = 2 $^6$ , x is odd)

∴ F = $\phi$ Since x $^2$ = 2 $^6$ = 64

x = $\pm 8$ which is even

∴ E ∩ F = $\phi$ Since there are no common elements

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