An electric bulb is rated 60W, 220V. Calculate the resist...
An electric bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally
296.7\(\Omega\)
400.0\(\Omega\)
512.2\(\Omega\)
806.7\(\Omega\)
Correct answer is D
P = \(\frac{v^2}{P} = \frac{220^2}{100} = 806.7\Omega\)
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