Find the sum to infinity to the following series 3 + 2 + $\frac{4}{3}$ + $\frac{8}{9}$ + $\frac{16}{17}$ + .....

1270

190

Correct answer is D

3 + 2 + $\frac{4}{3}$ + $\frac{8}{9}$ + $\frac{16}{17}$ + .....

a = 3

r = $\frac{2}{3}$

s $\alpha$ = $\frac{a}{1 - r}$ = $\frac{3}{1 - \frac{2}{3}}$

= $\frac{3}{\frac{1}{3}}$

= 3 x 3

= 9

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Find the sum to infinity to the following series 3 + 2 + $\frac{4}{3}$ + $\frac{8}{9}$ + $\frac{16}{17}$ + .....