Water of mass 120g at 50°C is added to 200g of water ...
Water of mass 120g at 50°C is added to 200g of water at 10°C and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]
60oC
40oC
25oC
10oC
Correct answer is C
120 x 4.2(50 - \(\theta\)) = 200 x 4.2(\(\theta\) - 10)
\(\theta = \frac{33600}{1344} = 25^oC\)
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