Water of mass 120g at 50°C is added to 200g of water ...
Water of mass 120g at 50°C is added to 200g of water at 10°C and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]
60oC
40oC
25oC
10oC
Correct answer is C
120 x 4.2(50 - θ) = 200 x 4.2(θ - 10)
θ=336001344=25oC
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