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If the angles of quadrilateral are (p + 10)°, (2p&n...

If the angles of quadrilateral are (p + 10)°, (2p - 30)°, (3p + 20)° and 4p°, find p.

A.

63

B.

40

C.

36

D.

28

Correct answer is C

The sum of angles in a quadrilateral = 360°

\therefore (p + 10) + (2p - 30) + (3p + 20) + 4p = 360

10p = 360° \implies p = \frac{360}{10} = 36°