A piece of metal of relative density 5.0 weighs 60N in ai...
A piece of metal of relative density 5.0 weighs 60N in air. Calculate its weight when fully immersed in water
4N
5N
48N
60N
Correct answer is C
R.D = \(\frac{m}{m - m_2} = 5 = \frac{60}{60 - m_1} = \frac{240}{5} = 48N\)
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