8\(\sqrt{3}\)
\(\frac{16}{\sqrt{3}}\)
\(\sqrt{3}\)
\(\frac{10}{\sqrt{3}}\)
Correct answer is A
\(\frac{x}{4}\) = \(\frac{\tan 60}{1}\)
x = 4 tan60
= 4\(\sqrt{3}\)
BD = 2x
= 8\(\sqrt{3}\)
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