(y + xy)(y + 2)(y - 2)
(y - xy)(y - 2)
y(1 + x)(y + 2)(y -2)
y(1 - x)(y + 2)(y - 2)
Correct answer is C
y3−4xy+xy3−4y
= \(y^3(1 + x) - 4y(1 + x)
(y3−4y)(1+x)=(y3(1+x)−4y(1+x))
∴ = y(1+x)(y+2)(y−2)
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