√−b±b2−4ac2a
−b±√p2−4pb2a
−q±√q2−4bp2p
−q±√p2−4bp2p
Correct answer is C
px2 + qx + b = 0
Using almighty formula
−b±√b2−4ac2a.........(i)
Where a = p, b = q and c = b
substitute for this value in equation (i)
= −q±√q2−4bp2p
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