a−b2a+b
2a+7ba−b
2a−7ba+b
2a+7ba+b
Correct answer is D
4a2−49b22a2−5ab−7b2 = (2a)2−(7b)2(a+b)(2a−7b)
= (2a+7b)(2a−7b)(a+b)(2a−7b)
= 2a+7ba+b
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