3
3√77
3√7
√7
Correct answer is B
cos2θ+18=sin2θ..........(i)
from trigometric ratios for an acute angle, where cos2θ+sin2θ=1 ........(ii)
Substitute for equation (i) in (i) = cos2θ+18=1−cos2θ
= cos2θ+cos2θ=1−18
2cos2θ=78
cos2θ=72×8
716=cosθ
√716 = √74
but cos θ = adjhyp
opp2=hyp2−adj2
opp2=42−(√7)2
= 16 - 7
opp = √9 = 3
tanθ=oppadj
= 3√7
3√7 x √7√7 = 3√77
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