A liquid of volume 2.00 m³ and density 1.00 x 10³ is mixed with 3.00 m³ of another liquid of density 8.00 x 10³kg m^-3. Calculate the density of the mixture [Assuming there is no chemical reaction]

5.20 x 10² kg m^-3

1.13 x 10³ kg m^-3

8.80 x 10² kg m^-3

5.20 x 10² kg m^-3

Correct answer is D

\(V_T = 5m^3, m_1 = 2 \times 1 \times 10^3 = 2 \times 10^3\)

\(M_2 = 3 \times 8 \times 10^3 = 24 \times 10^3\)

M_T = 26 x 10³

D = \(\frac{m}{v} = \frac{26 \times 10^3}{5} = 5.2 \times 10^3\)

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