y = 1(Z−x2)3
y = 1(Z+x2)13
y = 1(Z−x2)13
y = 13√Z−3√x2
Correct answer is C
Z = x2 + 1y3
Z - x2 = 1y3
y3 = 1Z−x2
y = 3√1Z−x2
∴ y = 13√Z−x2
y = 1(Z−x2)13
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