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If y = $\frac{x}{x - 3}$ + $\frac{x}{x + 4}$ find y when...

If y = $\frac{x}{x - 3}$ + $\frac{x}{x + 4}$ find y when x = -2

A.

- $\frac{3}{5}$

B.

$\frac{3}{5}$

C.

- $\frac{7}{5}$

D.

$\frac{2}{5}$

View answer & explanation

Correct answer is A

y = $\frac{x}{x - 3}$ + $\frac{x}{x + 4}$ when x = -2

y = $\frac{-2}{-5}$ + $\frac{(-2)}{-2 + 4}$

= $\frac{2}{5}$ + $\frac{-2}{2}$

= $\frac{4 -10}{10}$

= $\frac{-6}{10}$

= - $\frac{3}{5}$

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