In $\bigtriangleup$ XYZ, XY = 13cm, YZ = 9cm, XZ = 11cm and XYZ = $\theta$ . Find cos $\theta$ ^o

$\frac{4}{39}$

$\frac{43}{39}$

$\frac{209}{3}$

$\frac{43}{78}$

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Correct answer is D

cos $\theta$ = $\frac{13^2 + 9^2 - 11^2}{2(13)(9)}$

= $\frac{169 + 81 - 21}{26 \times 9}$

cos $\theta$ = $\frac{129}{26 \times 9}$

= $\frac{43}{78}$

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In $\bigtriangleup$ XYZ, XY = 13cm, YZ = 9cm, XZ = 11cm and XYZ = $\theta$ . Find cos $\theta$ ^o