A straight line y = mx meets the curve y = x2 - 12x + 40 ...
A straight line y = mx meets the curve y = x2 - 12x + 40 in two distinct points. If one of them is (5, 5) find the other
(5, 6)
(8, 8)
(8, 5)
(7,7)
(7, 5)
Correct answer is E
When y = 5, y = x2 - 12x + 40, becomes
x2 - 12x + 40 = 5
x2 - 12x + 40 - 5 = 0
x2 + 12x + 35 = 0
x2 - 7x - 5x + 35 = 0
x(x - 7) - 5(x - 7) = 0
= (x - 5)(x - 7)
x = 5 or 7
In the diagram, GI is a tangent to the circle at H. If EF||GI, calculate the size of ∠EHF ...
Simplify \( \frac{1}{(x + 1)} + \frac{1}{(x − 1)} \)...
Simplify \(\frac{1}{5x + 5}\) + \(\frac{1}{7x+ 7}\)...
In the figure, PQR is a semicircle while PQ and QR are chords. QS is the perpendicular fro...
In the diagram, angle QPR = 90o, angle PSR = 90o and PR = 5 units. Find the length of QS....