A straight line y = mx meets the curve y = x2 - 12x + 40 ...
A straight line y = mx meets the curve y = x2 - 12x + 40 in two distinct points. If one of them is (5, 5) find the other
(5, 6)
(8, 8)
(8, 5)
(7,7)
(7, 5)
Correct answer is E
When y = 5, y = x2 - 12x + 40, becomes
x2 - 12x + 40 = 5
x2 - 12x + 40 - 5 = 0
x2 + 12x + 35 = 0
x2 - 7x - 5x + 35 = 0
x(x - 7) - 5(x - 7) = 0
= (x - 5)(x - 7)
x = 5 or 7
If T = {prime numbers} and M = {odd numbers} are subsets of μ = {x : 0 < x ≤ ...
Factorize completely X2+2XY+Y2+3X+3Y-18 ...
Find the gradient of the line passing through the points (-2, 0) and (0, -4)...
The 6th term of a G.P is −227 and its first term is 18. What is the common ratio?...
Which of the following is equal to 72125...
In the figure, PQR is a straight line. Find the values of x and y ...