If w varies inversely as V and U varies directly as w³, Find the relationship between u and v given that u = 1, when v = 2

u = $\frac{8}{v^3}$

v = $\frac{8}{u^2v^3}$

u = 8v³

v = 8u²

Correct answer is A

W $\alpha$ $\frac{1}{v}$ u $\alpha$ w³

w = $\frac{k1}{v}$

u = k₂w³

u = k₂( $\frac{k1}{v}$ )³

= $\frac{k_2k_1^2}{v^3}$

k = k₂k₁k²

u = $\frac{k}{v^3}$

k = uv³

= (1)(2)³

= 8

u = $\frac{8}{v^3}$

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