Find $\alpha$ and $\beta$ such that x $\frac{3}{8}$ x y $\frac{-6}{7}$ x ( $\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}$ ) $\frac{1}{9}$ = $\frac{y^{\alpha}}{y^{\beta}}$

$\alpha$ = 1, $\beta$ = $\frac{5}{7}$

$\alpha$ = 1, $\beta$ = - $\frac{5}{7}$

$\alpha$ = $\frac{3}{5}$ , $\beta$ = -6

$\alpha$ = 1, $\beta$ = - $\frac{3}{5}$

Correct answer is A

x $\frac{3}{8}$ x y $\frac{-6}{7}$ x ( $\frac{y^{\frac{9}{7}}}{x^{\frac{45}{8}}}$ ) $\frac{1}{9}$ = $\frac{y^{\alpha}}{y^{\beta}}$

x $\frac{3}{8}$ x y $\frac{-6}{7}$ x y $\frac{1}{7}$ = x $\alpha$

= x $\frac{3}{8}$ + $\frac{5}{8}$ + y $\frac{6}{7}$ + $\frac{1}{7}$

= x $\alpha$ y $\beta$

x1y $\frac{-5}{7}$ = x $\alpha$ y $\beta$

$\alpha$ = 1, $\beta$ = $\frac{5}{7}$

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