(m2+n2)m+n
(m2+n2+2mn)4mn
2(m2+n2+mn)m+n
(m2+n2+mn)m+n
Correct answer is B
(m+n)2=(m−n)2+x2
m2+2mn+n2=m2−2mn+n2+x2
x2=4mn
x=√4mn=2√mn
1 + tan2θ = sec2θ
= 1cos2θ
cosθ=2√mn(m+n)
1cosθ=(m+n)2√mn
sec2θ=(m+n)24mn
= (m2+n2+2mn)4mn
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