2
4
100
0.4
0.1
Correct answer is D
y \(\alpha\) \(\frac{1}{x^2}\)
y = \(\frac{k}{x^2}\)
k = x2y
= (2)2 x 10
= 40
y = \(\frac{40}{x^2}\)
= \(\frac{40}{(10)^2}\)
= \(\frac{40}{100}\)
= 0.4
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