The positive root of t in the following equation, 4t2 + 7...
The positive root of t in the following equation, 4t2 + 7t - 1 = 0, correct to 4 places of decimal, is
1.0622
10.6225
0.1328
0.3218
2.0132
Correct answer is C
4t2+7t−1=0
Using a = 4, b = 7, c = -1.
x=−b±√b2−4ac2a
= −7±√72−4(4)(−1)2(4)
= −7±√49+168
= −7±√658
= −7±8.06238
The positive answer = −7+8.06238=1.06238
≊ (4 decimal place)
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