\(\frac{860}{3}\)
\(\frac{680}{3}\)
\(\frac{608}{3}\)
\(\frac{680}{3}\)
Correct answer is B
a = 153 - 1st term, 6th term = \(\frac{17}{27}\)
nth term = arn
Sn = a(1 - rn) where r < 1
6th term = 153\(\frac{1 - 0.4^4}{1 - 0.4}\)
= \(\frac{680}{3}\)
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