Two capacitors, each of capacitance 2μF are co...
Two capacitors, each of capacitance 2μF are connected in parallel. If the p.d across them is 120V, calculate the charge on each capacitor
6.0 x 10-5C
1.2 x 10-4C
2.4 x 10-4C
4.8 x 10-4C
Correct answer is C
C = C1+C2=2+2=4μF
but Q = CV
= 4 x 10−6 x 120
= 4.8 x 10−4
∴ Each of the capacitor has a charge of \frac{4.8 \times 10^{-4}}{2}
= 2.4 x 10^{-4} C
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