1.1 x 10-1J
5.5 x 10-2J
1.1 x 10-4J
5.5 x 10-8J
Correct answer is B
e = \(\frac{4FI}{Y \pi d^2} = \frac{4 \times 11 \times 10 \times 2}{7 \times 10^3 \times 3.14(2 \times 10^{-2})^2}\)
= 0.001m
E = \(\frac{1}{2} Fe = \frac{1}{2} \times 110 \times 0.001\)
= 5.5 x 10-2J
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