1.1 x 10-1J
5.5 x 10-2J
1.1 x 10-4J
5.5 x 10-8J
Correct answer is B
e = 4FIYπd2=4×11×10×27×103×3.14(2×10−2)2
= 0.001m
E = 12Fe=12×110×0.001
= 5.5 x 10-2J
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