6.3A
33.3A
37.2A
40.0A
Correct answer is A
XL = 2πfL
= = 2 x 3.142 x 50 x 0.12
= 37.68Ω
Z = √R2+X2L=√42+37.682
I = Vz=24037.89
= 6.3A
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