In the circuit diagram above, E is a battery of negligibl...
In the circuit diagram above, E is a battery of negligible internal resistance. If its emf is 9.0V. Calculate the current in the circuit
1.8A
1.0A
0.8A
0.3A
Correct answer is B
1r=1r1+1r2
= 15+120
= 4+120=520
r = 205
= 4Ω
R = R1 + R2
= 5 + 4
= 9Ω
but V = IR
I = VR=99
= 1A