A 40KW electric cable was uses to transmit electricity th...
A 40KW electric cable was uses to transmit electricity through a resistor of resistance 2.00Ω at 800V. The power loss as internal energy is
4.0 x 102W
5.0 x 102W
4.0 x 103W
5.0 x 103W
Correct answer is D
In general, Power = IV; ⟹40KW=IVTherefore 40000=1×800⟹I=40000800=50A,tune the current through
Resistor = 50A
power loss= I2R = 502 x 2
= 2500 x 2 = 5.0 x 103W
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