The radioisotope 23592U decays by emitting tw...
The radioisotope 23592U decays by emitting two alpha particles, three beta particles and a gamma ray. What is the mass and atomic number of the resulting element?
215 and 88
91 and 227
227 and 91
92 and 238
Correct answer is C
- Alpha radiation consists of helium- He42
2 Alpha decay --> 2 X He42 = Element84
- Beta particles are high energy electrons- e0−1
3 Beta particles --> 3 X e0−1 = Element0−3
- Gamma rays are waves of electromagnetic energy, or photons.
the mass and atomic number of the resulting element = U23592 - Elements( 84 + 0−3 )
--> Element22791
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