$in the image above, an incident ray XY makes an angle of 15$ ^{\circ} $ with a fixed line AY which is normal to surface of a plane mirror if the mirroe is turned as indicated by the arrow through $ 40^{\circ} $ what angle will the reflected ray make with AY$

in the image above, an incident ray XY makes an angle of 15 $^{\circ}$ with a fixed line AY which is normal to surface of a plane mirror if the mirroe is turned as indicated by the arrow through $40^{\circ}$ what angle will the reflected ray make with AY

$25^{\circ}$

$40^{\circ}$

$15^{\circ}$

$55^{\circ}$

$95^{\circ}$

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Correct answer is E

incident ray = XY

incidence angle i = 15 $^{\circ}$

rotation angle θ = 40º

angle that the reflected ray make with AY = i + 2θ

= 15 + [2 * 40] = 15 + 80 = 95º

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in the image above, an incident ray XY makes an angle of 15 $^{\circ}$ with a fixed line AY which is normal to surface of a plane mirror if the mirroe is turned as indicated by the arrow through $40^{\circ}$ what angle will the reflected ray make with AY