5 tan 25o sin 65o
5 cos 25o sin 65o
5 tan 25o cos 65o
cos 25o cos 65o
5 cosec 25o
Correct answer is C
From △QPR, < R = 180o - (25o + 90o)
180o - 115o = 65o
From △PSQ, Sin 65o = QPRhyp = PS5
PS = 5 sin 65o
From △PSR, tan = OPPadj = PSQS
but PS = 5 sin 65o
QS tan 25o = PS
QS tan 25o = 5 sin 65o
QS = 5sin65otan25o
= 5 tan 25o cos 65o
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