The work done in extending a spring by 40 mm is 1.52J. Ca...
The work done in extending a spring by 40 mm is 1.52J. Calculate the elastic constant of the spring.
38.8 Nm-1
60.8 Nm-1
190.0 Nm-1
1900.0 Nm-1
3800.0 Nm-1
Correct answer is D
Force = Elastic constant x extension
Work done = 12K×e2
Given Work done = 1.52J; Elastic constant (k) = ?; e = 40mm = 0.04 m
∴
3.04 = k \times 1.6 \times 10^{-3}
k = \frac{3.04}{1.6} \times 10^3
= 1.9 x 10^3
= 1900 Nm^{-1}
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