\(\frac{3}{39}\)
\(\frac{29}{36}\)
\(\frac{14}{5}\)
\(\frac{7}{5}\)
Correct answer is B
cos z = \(\frac{y^2 + x^2 -z^2}{2yx}\)
= \(\frac{9 + 36 - 16}{2(3)(6)}\)
= \(\frac{29}{36}\)
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