MN is tangent to the given circle at M, MR and MQ are two chords. IF QNM is 60o and MNQ is 40o. Find RMQ
120o
110o
60o
20o
Correct answer is D
QMN = 60o
MRQ = 60o(angle in the alternate segment are equal)
MQN = 80o(angle sum of a \(\bigtriangleup\) = 180o)
60 = x = 80o(exterior angle = sum of opposite interior angles)
x = 80o - 60o = 20o
RMQ = 20o
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