In the diagram, O is the centre of the circle. If SOQ is a diameter and < PRS is 38o, what is the value of < PSQ
148o
104o
80o
52o
Correct answer is D
< SRP = < SQP = 38o (angle in the same segment of a circle are equal)
But < SPQ = 90o (angle in a semicircle)
also < PSQ + < SQP + < SPQ = 180o (angles in a triangle = 180o)
< PSQ + 38o + 90o = 190o
< PSQ = 128o = 180o
PSQ = 180o - 128o
PSQ = 52o
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