$In the figure, XYZ is a triangle with XY = 5cm, XZ = 2cm and XZ is produced to E making the angle < YZE = 150o. If the angle XYZ = $\theta$, calculate the value of sin$\theta$$

In the figure, XYZ is a triangle with XY = 5cm, XZ = 2cm and XZ is produced to E making the angle < YZE = 150^o. If the angle XYZ = $\theta$ , calculate the value of sin $\theta$

$\frac{3}{5}$

$\frac{1}{2}$

$\frac{2}{5}$

$\frac{1}{5}$

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Correct answer is D

$\frac{5}{\sin 36^o} = \frac{2}{\sin \theta} = \frac{5}{\frac{1}{2}} = \frac{2}{\sin \theta}$

10 = $\frac{2}{\sin \theta}$

sin $\theta$ = $\frac{2}{10}$

= $\frac{1}{5}$

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In the figure, XYZ is a triangle with XY = 5cm, XZ = 2cm and XZ is produced to E making the angle < YZE = 150^o. If the angle XYZ = $\theta$ , calculate the value of sin $\theta$

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