find the length XZ in the triangle
√7m
√6m
√5m
√3m
Correct answer is A
xz2 = xy2 + yx2 - 2(xy) (yz) cos 120o = 22 + 12 - 2(2) (1) cos 1202 = 4 + 1 - 4x - cos 60 = 5 - 4x - 12 5 + 2 = 7 xz = √7m
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