In the figure PQR a straight line segment, PQ = QT. Triangle PQT is an isosceles triangle, < SRQ is 75o and < QPT IS 25o. Calculate the value of < RST
50o
25o
55o
45o
Correct answer is C
< T = \(\frac{x}{1}\) = 25o (PQ = QT)
< SQR = 2(25o) = 50o (sum of interior angle)
< Q + < R + < S = 180o
50o + 75o + < S = 180o = 125o + < S = 180o
< S = 180o - 125o = 55o
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