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in a nuclear fission process, the mass defect was 1.2 x 10

in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]

A.

1.08 x 1011J

B.

5.20 x 1011J

C.

1.08 x 1012J

D.

2.50 x 1013J

View answer & explanation

Correct answer is C

E - Mec2

E = 1.2 x 10-5 x (3 x 108)2

E = 1.08 x 1012J

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