An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10 $^{-5}$ K $^{-1}$

155^oC

160^oC

169^oC

179^oC

Correct answer is D

$\alpha = \frac{L_2 - L_1}{L_1(\theta_2 - \theta_1)}$

L $_2$ - L $_1$ = $\alpha L_1 (\theta_2 - \theta_1)$

$\theta_2 = \frac{0.007}{2.3 \times 10^{-5} \times 1.8}$ + 10

= 179°C

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An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10 $^{-5}$ K $^{-1}$

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An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10−5^{-5}K−1^{-1}

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An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10 $^{-5}$ K $^{-1}$