Calculate the electric field intensity between two plates...
Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.
18.57NC−1
53.06N C−1
2.28NC−1
0.80NC−1
Correct answer is A
Electric Field Intensity (E) = vd
= potential differencedistance
= 6.5v35cm
= 6.535×10−2
= 18.57NC−1
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