\(\begin{array}{c|c} x & 1 & 4 & p \\ \hline ...
x14py0.512.5. The table below satisfies the relation y - k√x, where k is a positive constant. Find the value of P,
2
4
10
25
Correct answer is D
From y = 12√x
when y = 2.5 or 52, x = P
52×12√P
√P=102=5
P = 52
= 25
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