A machine valued at N20,000 depreciates by 10% every year...
A machine valued at N20,000 depreciates by 10% every year. What will be the value of the machine at the end of two years?
N16,200
N1,4,200
12,000
8000
Correct answer is A
D = P(I - R100)n where P = N20,000; R = 10%, n = 2
D = 20,000(I - 10100)2
= 20000(0.9)2
20,000 x 0.81 = N16,200
solve the equation cos x + sin x 1cosx−sinx for values of such that 0 ≤ x < 2...
Points X and Y are respectively 12m North and 5m east of point Z. Calculate XY ...
Using △XYZ in the figure, find XYZ...
Find the value of 1101112 + 101002...