Water of mass 150g at 60oc is added to 300g of water...
Water of mass 150g at 60oc is added to 300g of water at 20oc and the mixture is well stirred. Calculate the temperature of the mixture.(neglect heat losses to the surroundings)
33oc
40oc
25oc
10oc
Correct answer is A
Water 1 => M = 150g = 0.15kg,
θ2 = 60oC; θ1 = θ
Q1 = MC (θ2 – θ1)
= 0.15C (60 - θ)
Water 2 => M = 300g = 0.3kg
θ1 = 20oC, θ2 = θ
Q2 = MC (θ2 – θ1)
= 0.3C (θ – 20)
Combining Q1 and Q2
0.15C (60 - θ) = 0.3C (θ – 20)
9 – 0.15θ = 0.3θ – 6
0.3θ + 0.15θ = 9 + 6
0.45 θ = 15
θ = 33.33oC
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