A ball of mass 5.0kg hits a smooth vertical wall normally...
A ball of mass 5.0kg hits a smooth vertical wall normally with a speed of 2ms−1. Determine the magnitude of the resulting impulse
20.0kgms−1
10.0kgms−1
5.0kgms−1
2.5kgms−1
Correct answer is B
Impulse = Change in momentum
m (v - u)
5 (2.0)
= 5 x 2 = 10.0kgm−1
= 10.0kgms−1
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